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-6x^2+17x+3=0
a = -6; b = 17; c = +3;
Δ = b2-4ac
Δ = 172-4·(-6)·3
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-19}{2*-6}=\frac{-36}{-12} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+19}{2*-6}=\frac{2}{-12} =-1/6 $
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